donhoop726 donhoop726
  • 03-09-2018
  • Biology
contestada

A 130-lb person burns about 2300 calories to run a marathon how much energy is burned in kj chemistry

Respuesta :

transitionstate
transitionstate transitionstate
  • 12-09-2018

Data given

                 Energy burned in calorie = 2300 calorie

Required

              Energy burned in Kj = ?

Solution

               As we know that  

             1Cal = 0.0041868kj

            So 2300 Cal = 2300 x 0.0041868

            = 9.6294 Kj  (answer)



energy burned in kj = ?

As we know that  

1Cal= 0041868kj

So 2300 Cal= 2300 x 0.0041868 = 9.6294 Kj


Answer Link

Otras preguntas

Help please anyone please!!!!
find the missimg side and round to the nearest tenth​
Help me please! Who is less skillful
. True or False? Write your response next to the statements below. A) Sam computed a 90% confidence interval for µ from a specific random sample of size n. He c
2X+20 and X+60 I have to solve for X
What do you think caused this land formation ?
a wooden block with a mass of 2.0kg starts from at the top of an inclined plane and ends with a force of 25N at the bottom what was the rate of acceleration of
which coordinate plane represents the linear relationship 4x + 5y = 20
The cost of 5 litres of milk is Rs. 55. Tabulate the cost of 2, 4 and 10 litres of milk please help me complete the table​
from the elegant universe