winton2005212p44hkh winton2005212p44hkh
  • 04-05-2020
  • Physics
contestada

A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m. What was its acceleration?

Respuesta :

PhantomWisdom PhantomWisdom
  • 10-05-2020

Answer:

Acceleration, [tex]a=3.08\ m/s^2[/tex]      

Explanation:

We have,

Initial speed of the car, u = -27.7 m/s

Final speed, v = -10.9 m/s

Displacement, d = -105 m

It is required to find acceleration of the car. Acceleration of an object is equal to the change in velocity divided by time.

The relation between displacement, velocity and acceleration is given by third equation of motion.

[tex]v^2-u^2=2ad[/tex]

a is acceleration

[tex]a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(-10.9)^2-(-27.7)^2}{2(-105)}\\\\a=3.08\ m/s^2[/tex]

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