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  • 03-09-2016
  • Mathematics
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solve the following equation. 2x - 1 ≤ x 5

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Аноним Аноним
  • 04-09-2016

2x−1≤x5

Let's find the critical points of the inequality.

2x−1=x^5

2x−1−x^5=x^5−x^5 (Subtract x^5 from both sides)

−x^5+2x−1=0

(−x+1)(x^4+x^3+x^2+x−1)=0  (Factor left side of equation)

−x+1=0 or x^4+x^3+x^2+x−1=0   (Set factors equal to 0)

x=1 or x=0.51879 or x=−1.290649
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