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Two cyclists start from the same point at the same time and move in opposite directions. One cyclist is traveling at 7 mph, and the other cyclist is traveling at 11 mph. After 30 min, how far apart are the two cyclists? mi Need Help? Read it Watch​

Respuesta :

quasarJose

Given parameters:

Speed of Cyclist 1  = 7mph

Speed of Cyclist 2 = 11mph

Time of travel  = 30min  = 0.5hr(60min  = 1hr)

Unknown:

Distance separating them  = ?

To solve this problem, we must understand that speed is the distance per unit time traveled.

Mathematically;

           Speed  = [tex]\frac{Distance}{Time}[/tex]

Now we are to find the distance separating the two cyclists;

           Distance  = speed x time

To find the distance separating the two cyclists, find the sum of their individual distances covered.

 Distance separating them = Distance covered by cyclist 1   + Distance covered by cyclist 2

Now input the parameters;

       

Distance of separation =  (7 x 0.5)   +  (11 x 0.5)   = 3.5 + 5.5 = 9miles

The distance separating them is 9miles

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