Answer:
The resulting force on the first object is 800 N.
Explanation:
Given;
force exerted on one of the objects, F₁ = 400 N
let the first charge = q₁
let the second charge = q₂
The force of repulsion between the objects is calculated using Coulomb's law;
[tex]F =\frac{kq_1q_2}{r^2} \\\\\frac{k}{r^2} = \frac{F}{q_1q_2} = \frac{F_1}{q_1\times2q_2} \\\\F_1 = \frac{F(q_1\times2q_2)}{q_1q_2} \\\\F_1 = 2F\\\\F_1 = 2(400 \ N)\\\\F_1 = 800 \ N[/tex]
Therefore, the resulting force on the first object is 800 N.
