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A parabola drawn on a coordinate plane has vertex (1,āˆ’2) and focus (4,āˆ’2) . The parabola opens to the right. Which of the following is an equation of this parabola

Respuesta :

Answer: (y+2)^2 =12(x-1)

Step-by-step explanation:

Step 1 Find the distance from the vertex to the focus. \(p=4-1=3\)

Step 2 Use the vertex and focus to find the equation of the parabola. \((y-(-2))^{2}=4\cdot 3(x-1)\) \((y+2)^{2}=12(x-1)\)

Solution The equation of the parabola is \((y+2)^{2}=12(x-1)\).

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