For this problem, we use the derived equations for rectilinear motion at constant acceleration. The equation is:
a = (v -vâ‚€)/t
where
v and vâ‚€ is the final and initial velocities, respectively
t is time
a is acceleration
Since it eventually comes to a stop, v=0. Substituting the values,
a = (0 - 7.68 m/s)/0.202 s
a = -38.02 m/s²
Hence, the magnitude of the acceleration is -38.02 m/s². The direction is still aiming along the straight line, but the negative sign signifies that the the ball is decelerating.
